Tips on utilizing the each(..) method in typescript?

Question

Tips on utilizing the each(..) method in typescript?

_.each(key_val, function(e){
            if($.inArray(e[0], names) == -1){
                var node = {};
                node.name = e[0];
                if(e[1]) {
                    node.value = e[1];
                    node.symbolSize = e[1] * nodeProp;
                }
                optionNodes.push(node);
                names.push(e[0]);
            }
        });

The code snippet above utilizes angular.js and I need to integrate it into an angular typescript environment. In this case, "key_val" represents an array.

angular typescript underscore.js

Answer 1

Answer №1

If you want to achieve the functionality of your function, one approach is to create an array of objects with 'name' and 'value' keys as shown below:

let data = [{name: 'x', value: 'abc'}, {name: 'y', value: ''}];

Let's assume you also have a list of names like this:

let items = ['p', 'q'];

To loop through each object in the 'data' array, you can utilize the map method in the following way:

data.map(object => {
  if(items.indexOf(object.name) === -1) {
    let newData = {};
    newData.name = object.name;
    if(object.value) {
       newData.value = object.name;
       newData.size = object.name * sizeFactor;
    }
    updatedData.push(newData);
    items.push(object.name);
  }
});

Answer 2

If you want to achieve the functionality of your function, one approach is to create an array of objects with 'name' and 'value' keys as shown below:

let data = [{name: 'x', value: 'abc'}, {name: 'y', value: ''}];

Let's assume you also have a list of names like this:

let items = ['p', 'q'];

To loop through each object in the 'data' array, you can utilize the map method in the following way:

data.map(object => {
  if(items.indexOf(object.name) === -1) {
    let newData = {};
    newData.name = object.name;
    if(object.value) {
       newData.value = object.name;
       newData.size = object.name * sizeFactor;
    }
    updatedData.push(newData);
    items.push(object.name);
  }
});

Tips on utilizing the each(..) method in typescript?

Answer №1

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