Traverse an array while maintaining the discriminating union type

Here is an array I have:

const myArray: (
  | { feature1: true; feature2: [number, number] }
  | { feature1: false; feature2: [number, number, number] }
)[] = [
  { feature1: true, feature2: [1, 2] },
  { feature1: false, feature2: [3, 4, 5] },
];

I want to multiply all the numbers in this array by two. This is what I am trying to do:

// Please don't scrutinize this function, it's accurate
export const modifyElements = <T extends unknown[], R>(
  array: T,
  callback: (value: T[number], index: number, array: T) => R,
): { [K in keyof T]: R } =>
  array.map(
    callback as (value: unknown, index: number, array: unknown[]) => R,
  ) as { [K in keyof T]: R };

const modifiedResult: typeof myArray = myArray.map(({ feature1, feature2 }) => ({
  feature1,
  feature2: modifyElements(feature2, (x) => x * 2),
}));

However, it shows an error

Type 'boolean' is not assignable to type 'false'
.

To solve this issue, I am currently using a somewhat ridiculous ternary operator:

const modifiedResult: typeof myArray = myArray.map(({ feature1, feature2 }) =>
  feature1
    ? { feature1, feature2: modifyElements(feature2, (x) => x * 2) }
    : { feature1, feature2: modifyElements(feature2, (x) => x * 2) },
);

Is there a more elegant solution for this problem?

Answer №1

Perhaps this solution may not be exactly what you need as it involves casting, but it is a potential approach to the problem.

const modifiedArray: typeof originalArray = originalArray.map(({ key1, key2 }) =>
  ({ key1, key2: manipulateTuple(key2, (value) => value * 2) }) as (typeof originalArray)[number]
);

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