I’m working on a function that accepts two other functions (fn1 and fn2) as parameters. These functions should have the same number of arguments with the same types, but different return types.
Is there a method to ensure that both functions have identical argument types?
function myFunction(fn1: Function, fn2: (...args: any[]) => string): number {
return 0;
}
To extract argument types from the first function and define the second function based on these extracted arguments, you can utilize conditional types along with tuples in rest parameters.
type ArgTypes<T> = T extends (...a: infer A) => unknown ? A : []
function myFunction<T extends (...a: unknown[]) => unknown>(fn1: T, fn2: (...a: ArgTypes<T>) => string): number {
return 0;
}
myFunction((s: string) => s, (s: string) => s) // This is valid
myFunction((s: string) => s, (s: number) => s.toString()) // This will result in an error
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