TypeScript allows for the declaration of a function that includes a mandatory property within the function signature

If I desire a tagged function with an interface such as:

interface TaggedFun {
    (args): void;
    tag: boolean;
}

It appears that declaring a function to match this signature is not possible (since any function literal will lack the mandatory tag property);

The only recourse is to make tag optional and then remember to assign a value to it later.

Is there a method to uphold type safety (i.e. enforce the tag requirement in the type)?

Answer №1

To instantiate objects of TaggedFun, you can utilize a factory method:

interface TaggedFun {
    (): void;
    tag: boolean;
}

function createTaggedInstance(tag: boolean, fn?: () => void): TaggedFun {
    let tagged = (fn || function () {
        // add function logic here
    }) as TaggedFun;

    tagged.tag = tag;
    return tagged;
}

This approach ensures the presence of the tag property in instances created through the factory, providing type safety.
Here's an example:

function performAction(tagged: TaggedFun) {}

performAction(() => { }); // error 
performAction(createTaggedInstance(true)); // okay
performAction(createTaggedInstance(true, () => { })); // okay

(code in playground)

Answer №2

Doing it in a more unconventional manner, the approach you mentioned seems suitable.

This is tailored for accommodating legacy javascript practices where functions are adorned with additional attributes instead of utilizing classes.

I strongly recommend opting for a class implementation instead.

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