Typescript: comparing 2 arrays

Is there a more efficient method for determining if two arrays have common elements?

In languages like Java, I would utilize streams and lambda expressions.

lst1.stream().anyMatch(c -> lst2.contains(c))

However, I am unsure of how to achieve this in Typescript/Javascript.

let lst1: string[] = ["aaa", "bbb", "ccc"];
let lst2: string[] = ["ddd", "eee", "bbb"];    // 1 match at "bbb";

let matches: boolean = false;
for (let a of this.lst1)
{
    for (let b of this.lst2)
    {
        if (a === b)
        {
            matches = true;
        }
    }
}

Answer №1

Have you considered using the some function along with the includes function?

For instance:

you can try implementing it like this: const matches = this.lst1.some(x => this.lst2.includes(x))

Answer №2

Filtering lst1 based on elements that are also found in lst2

Resultant array will contain overlaps

Answer №3

In the realm of Javascript, there are handy array functions that can assist in simplifying tasks like the one at hand. One particularly useful function is Array.prototype.filter.

This question has actually been posed in the past, so it might be beneficial to refer back to this response (or others related to this issue):

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