Typescript: Convert Generics to a String Format

Is there a way for me to return a generic type as a string in this function?

const actionName = <P extends string>(path: P) => <A extends string>(action: A): string => `${path}/${action}`;

const path = actionName('filter');
const action = actionName('OPEN');

The expected type in action is 'filter/OPEN', but I am only getting 'OPEN'

Answer №1

Avoid using strings for literal types in your code.

Here's a demonstration of how you can implement it with a generic type that suits your scenario:

const actionIdentifier = <T extends "search" | "Order">(endpoint: T) => <
  U extends "START" | "STOP"
>(
  operation: U,
) => `${endpoint}/${operation}` as `${T}/${U}`;

const endpoint = actionIdentifier("search")("START");

Answer №2

The issue stemmed from the correct utilization of the generic function. The function actionName is constructing a function within another function, requiring a nested invocation to access all its levels. Initially, path establishes the path as 'filter', while action further defines the action as 'OPEN' within path. To achieve the desired output, follow this:

const actionName = <P extends string>(path: P) => <A extends string>(action: A): string => `${path}/${action}`;

const path = actionName('filter');
const action = path('OPEN');

console.log(typeof action, action);
//string filter/OPEN

Answer №3

Situation rectified!

const actionCreator = <P extends string>(path: P) => <A extends string>(action: A): `${P}/${A}` => `${path}/${action}` as `${P}/${A}`;

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