TypeScript does not raise errors for ANY variables that are initialized later

In my code, there is a function that accepts only numeric variables.

function add(n1: number) {
    return n1 + n1;
}

However, I mistakenly initialized a variable with type "any" and assigned it a string value of '5'.

let number1;
number1 = '5';

I was surprised to see that no error was thrown when passing this string variable to the function.

console.log(add(number1));

(As expected, the result is 55 as the string gets concatenated instead of added.)

Answer №1

When the type is either not specified (implicit any) or explicitly set to any, the variable's uses will not undergo type checking. This functionality can be particularly beneficial when gradually transitioning JavaScript code to TypeScript.

To identify implicit any's, such as the one in your example, as errors, you can utilize the noImplicitAny compiler flag.

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