Typescript - Ensuring object assignment with additional property does not result in failure

What is the reason why the code does not fail when executing a = b ? Check out this link

type A = {
    x?: number
    y?: number
}

type B = {
    x?: number
    z: number
}

let a: A = {}
let b: B = {z: 1}

a = b // does not fail
a = {z: 1} // fails

Answer №1

Typescript uses structural typing (Wikipedia), where an object of type B is considered a valid A object.

In the second scenario, excess property checks will prevent you from assigning a literal that shares no similarities with A.

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