TypeScript - Issue with generic function's return type

There exists a feature in typescript known as ReturnType<TFunction> that enables one to deduce the return type of a specific function, like this

function arrayOf(item: string): string[] {
  return [item]
}

Nevertheless, I am encountering difficulties when trying to utilize it with generic functions:

function arrayOf<T>(item: T): T[] {
  return [item]
}

type R = ReturnType<typeof arrayOf> // R = {}[]
type R = ReturnType<typeof arrayOf<number>> // syntax error
// and so on.

Utilizing the primary answer from Typescript ReturnType of generic function, I have attempted the following: (note that this is not a duplicate, as the solution and question do pertain to this scenario)

function arrayOf<T>(x: T): T[] {
  return [x];
}

type GenericReturnType<R, X> = X extends (...args: any[]) => R ? R : never;

type N = GenericReturnType<number, <T>(item: T) => T[]>; // N = never

I have also experimented with:

type GenericReturnType<TGenericParameter, TFunction> = TFunction extends (...args: any[]) => infer R ? R : never;

type N = GenericReturnType<number, <T>(item: T) => T[]>; // N = {}[]

as well as

type GenericReturnType<TGenericParameter, TFunction> = TFunction extends <T>(...args: any[]) => infer R ? R : never;

type N = GenericReturnType<number, <T>(item: T) => T[]>; // N = {}[]

and further tried

type GenericReturnType<TGenericParameter, TFunction> = TFunction extends <T extends TGenericParameter>(...args: any[]) => infer R ? R : never;

type N = GenericReturnType<number, <T>(item: T) => T[]>; // N = {}[]

also this

type GenericReturnType<TGenericParameter, TFunction> = TFunction extends (arg: TGenericParameter) => infer R ? R : never;

type N = GenericReturnType<number, <T>(item: T) => T[]>; // N = {}[]

as well as

type x = (<T>(item: T) => T[]) extends <T>(arg: T) => infer R ? R : never // x = {}[]

and lastly

type x = (<T>(item: T) => T[]) extends (arg: number) => infer R ? R : never // x = {}[]

However, none of them provide the desired type of number[]

Therefore, my query is, is there any method to develop something akin to the built-in ReturnType that functions for functions with generic parameters, taking into account the types of said generic parameters? (or, a resolution to the issue presented above)

Answer №1

Dealing with the same issue as you, I finally stumbled upon a clever "hack" after trying numerous unsuccessful workarounds. However, please note that this solution may not be suitable for all scenarios:

Following Matt's suggestion, the key is to create a dummy function without actually rewriting it. Instead of crafting a duplicate version of your function, develop a dummy function that generates a mock usage of your function. Then, utilize ReturnType to extract the resulting type:

function arrayOf<T>(item: T): T[] {
    return [item];
}

const arrayOfNumber = () => arrayOf<number>(1);
type N = ReturnType<typeof arrayOfNumber>;

As of TypeScript 3.7, unless I have missed something in my investigation, achieving the desired outcome directly still remains challenging without resorting to a workaround. Hopefully, a more straightforward solution like the one below becomes available soon:

function arrayOf<T>(item: T): T[] {
    return [item];
}

type N = GenericReturnType<typeof arrayOf>; // N<T>

Answer №2

When examining the type arguments for this particular function, it becomes evident that you can navigate through a series of links to uncover more information at Getting the return type of a function which uses generics. By analyzing the argument types, you have the ability to create a non-generic placeholder function that accepts arguments of those specific types. Subsequently, you can verify its return type by implementing the following:

function dummy(n: number) { return arrayOf(n); }
type N = ReturnType<typeof dummy>;

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