Typescript: The ConstructorParameters type does not support generics

Incorporating TypeScript 3.7, I created an interface featuring a property designed to accept a constructor function:

interface IConstruct<T> {
  type: new (...args:ConstructorParameters<T>) => T;
}

I initially assumed that IConstruct<User> would include a property {type: User}.
However, the compiler is indicating that T cannot be utilized in this context. What is the reason for this error message?

TS2344: Type T does not satisfy the constraint 'new (...args: any) => any'

Answer №1

In the case of ConstructorParameters, the structure appears as follows:

type ConstructorParameters<T extends new (...args: any) => any> =
  T extends new (...args: infer P) => any ? P : never;

Therefore, the type parameter T must be an extension of a constructor function defined by the constraint

extends new (...args: any) => any
. By structuring the example above in this manner, you should have a solid foundation:

class User {
    constructor(public name: string) { }
}

// include constructor function type constraint for T
interface IConstruct<T extends new (...args: any) => any> {
    // InstanceType can be used to infer instance type from class type
    type: new (...args: ConstructorParameters<T>) => InstanceType<T>;
}

type UserConstruct = IConstruct<typeof User>

const constr: UserConstruct = {
    type: User
}

constr.type // new (name: string) => User

const userInstance = new constr.type("John") // userInstance: User

console.log(userInstance.name) // John

Playground

Answer №2

The issue has been successfully resolved: https://github.com/microsoft/TypeScript/issues/31278

Personally, I found that the missing typeof was causing the problem:

class Parent<T> {
    constructor(readonly data: T) {
    }
}
class Child<T> extends Parent<T> {
    constructor(...args: ConstructorParameters<typeof Parent<T>>) {
        super(...args);
    }
}

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