Is there a way to create a new object type that includes only properties from another Object that match specific types, as opposed to property names?
For example:
interface A {
a: string;
b: number;
c: string[];
d: { [key: string]: never };
}
interface B extends PickPropertyTypes<A, string | number>{}
In this case, interface B should only contain properties a: string and b: number, resulting in an interface like:
{
a: string;
b: number;
}
Is this achievable? Thank you.
Defined interface A with properties a, b, c, and d
Created PickPropertyTypes type to pick specific property types from an object type
Used PickPropertyTypes type on interface A with string or number type filtering
Need clarification on the syntax used for defining type B
One alternative solution to the existing one is to start by creating a helper type that extracts keys of a specified type, but only those keys that meet certain criteria.
Then, this helper type can be utilized to construct the actual structural type.
interface B {
x: string;
y: number;
z: string[];
w: { [key: string]: never };
}
type ExtractKeyTypes<T, U> = { [K in keyof T]: T[K] extends U ? K : never; }[keyof T]
type SelectKeyTypes<T, V> = { [K in ExtractKeyTypes<T, V>]: T[K] }
type Result = SelectKeyTypes<B, string | number>
This method mirrors how Pick is based on Extract, and Omit is built upon Exclude.
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