TypeScript's type 'T' has the potential to be instantiated with any type, even if it is not directly related to 'number'

Let's say we have a function that takes a value (for example, number) and a callback function that maps that value to another value. The function simply applies the provided callback:

function mapNumber<T>(value: number, mapfn: (value: number) => T) {
  return mapfn(value);
}

We want to set identity as the default argument for the callback in case no callback is provided by the user:

function identity<T>(x: T) {
  return x;
}
    
// Error: Type '<T>(x: T) => T' is not assignable to type '(value: number) => T'.
  // Type 'number' is not assignable to type 'T'.
   // 'T' could be instantiated with an arbitrary type which could be unrelated to 'number'
function mapNumber<T>(value: number, mapfn: (value: number) => T = identity) {
  return mapfn(value);
}

What might be causing this problem? In theory, since mapfn is in a contravariant position, it should accept any callback function that is more general than (value: number) => T, so identity should suffice, right?

Answer №1

It has been pointed out in the comments that the issue lies in your code's ability to define T as something other than a number. This results in your identity function being of the wrong type for mapfn, as identity returns the same type it receives, which in this case is number instead of the expected type T.

In the example mapNumber<string>(10), the type parameter T is string, but mapfn (using identity) returns number instead of string.

To address this issue, one possible solution is to cast identity as any to remove the error from the mapNumber function definition. However, this approach does not provide a warning for the potential issue and can lead to bugs later in your code.

Instead, it is recommended to overload the definition of mapNumber so that there is a specific case for T = number where mapfn is optional.

function identity<T>(x: T) {
    return x;
}

function mapNumber(value: number, mapfn?: (value: number) => number): number;
function mapNumber<T>(value: number, mapfn: (value: number) => T): T;
function mapNumber<T>(value: number, mapfn: (value: number) => T = identity as any) {
    return mapfn(value);
}

Example usage:

// allowed:
mapNumber(10)
mapNumber(10, (x) => x * 10)
mapNumber(10, (x) => x.toString())
mapNumber<string>(10, (x) => x.toString())

// not allowed:
mapNumber<string>(10)

It is important to note that the any cast is necessary for types to work with the base signature of mapNumber. In this case, identity serves as a default value only for the first overload signature when T is number.

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