Typescript's usage pattern for Observable<void>

When dealing with an async service that does not have a return value but requires the use of Observables, I often find myself using Observable<boolean>. However, in reality, I do not need to assign any meaning to this boolean value because the service either fails or succeeds. If it fails, I want the Observable to be in the error state, leaving only 'true' values for observation.

Is utilizing Observable<void> a suitable pattern for such scenarios? Are there any potential issues with using Observable<void>?

const asyncFuncWithoutResult = (): Observable<void> => {
  // Simulate an asynchronous operation with no return value

  const itWorked = true; // or not
  if (itWorked) {
    return Observable.of();
  } else {
    return Observable.throw(Error('It did not work'));
  }
}

// Call the service
asyncFuncWithoutResult()
  .subscribe(
    undefined, // Nothing will be emitted when using Observable.of()
    (err: any) => console.error(err), // Handle error state
    () => console.log('Success'),     // Handle success state
  );

Answer №1

To provide more accuracy, when you create a Subject using the generic type void, there are two ways to invoke its next() method without providing any arguments:

const subject = new Subject<void>();
subject.next();

...or by using void 0:

subject.next(void 0);

It's important to note that the value parameter for next is optional, so if left unspecified, it will default to sending undefined. This means that even with a Subject<void>, you will still receive notifications from next:

asyncFuncWithoutResult().subscribe(alwaysUndefined => {
  /* ... */
});

Additionally, you have the ability to convert any Observable into <void> (which is often necessary when combining multiple Observables) using the map operator:

source.pipe(map(() => void 0))
   ...

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