Unable to use console log in shorthand arrow function while working with Typescript

When debugging an arrow function in JavaScript, you can write it like this:

const sum = (a, b) => console.log(a, b) || a + b;

This code will first log a and b to the console and then return the actual result of the function. However, when using TypeScript, an error may occur stating that console.log cannot be tested for truthiness:

An expression of type 'void' cannot be tested for truthiness

While this error seems valid, this method is a handy trick for debugging arrow functions, and I would prefer not having to add curly braces to every arrow function if possible.

Even though the console log is temporary, is there any way to make TypeScript accept this pattern without using @ts-ignore?

Answer №1

Transform the following code to utilize the comma operator:

const printer = (x, y) => (console.log(x, y), x * y);

Answer №2

To resolve this issue, you can convert the console.log expression to a boolean.

Here is an example:

const sum = (a, b) => Boolean(console.log(a, b)) || a + b;

By converting the console.log output to boolean, it will always result in false, making sure the subsequent expressions are executed as expected.

Answer №3

If you want to customize the behavior of the console type, you can do so by declaring it with your desired modifications. This way, you only need to make the adjustments once instead of changing every call to console.log:

declare const console = {
    log: (...args: unknown[]) => undefined,
    // additional customizations
};

const sum = (a: number, b: number) => console.log(a, b) || 'foo';
const another = (a: number, b: number) => console.log(a, b) || 'bar';

Answer №4

This is my preferred approach:

const addition = (x, y) => x + y && alert(x, y);

I hope this suggestion works for you! :)

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