Unlawful manipulation of filtering in typescript

Question

Unlawful manipulation of filtering in typescript

My task involves sifting through an array of objects to separate them based on their status codes. If the item has a status code of 1, I store it in the openIssue array; if it has a status code of 3, it goes into the inProgressIssue array.

This is the relevant portion of my code:

openIssue = [];
inProgressIssue = [];
issuesNotCompletedInCurrentSprint.forEach((item) => {
  if (item.statusId === '1') {
    openIssue.push(item);
  } else if (item.statusId === '3') {
    inProgressIssue.push(item);
  }
});

I received feedback during a code review stating:

Illegal use of filter

I'm seeking advice on how to correct this issue. Can someone please provide guidance?

angular typescript

Answer 1

Answer №1

The error occurred because the filter function in JavaScript expects a boolean return value. It is designed to iterate over an array and filter out elements based on a condition that returns true or false. I recommend using the filter function like this, as it is quite simple. Alternatively, you can also use the forEach function which does not require a return value.

openIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '1');
inProgressIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '3');

In this code snippet, the filter function will return the elements with statusId equal to '1' and '3', respectively.

let issuesNotCompletedInCurrentSprint = [{
  statusId: '1',
  name: 'asfadsf'
}, {
  statusId: '2',
  name: 'asfadsf11'
}, {
  statusId: '3',
  name: 'asfadsf6636'
}];
let openIssue = [];
let inProgressIssue = []
openIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '1');
inProgressIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '3');

console.log('open', openIssue, 'inprogress', inProgressIssue)

Answer 2

The error occurred because the filter function in JavaScript expects a boolean return value. It is designed to iterate over an array and filter out elements based on a condition that returns true or false. I recommend using the filter function like this, as it is quite simple. Alternatively, you can also use the forEach function which does not require a return value.

openIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '1');
inProgressIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '3');

In this code snippet, the filter function will return the elements with statusId equal to '1' and '3', respectively.

let issuesNotCompletedInCurrentSprint = [{
  statusId: '1',
  name: 'asfadsf'
}, {
  statusId: '2',
  name: 'asfadsf11'
}, {
  statusId: '3',
  name: 'asfadsf6636'
}];
let openIssue = [];
let inProgressIssue = []
openIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '1');
inProgressIssue = issuesNotCompletedInCurrentSprint.filter(a => a.statusId === '3');

console.log('open', openIssue, 'inprogress', inProgressIssue)

Answer 3

Answer №2

An error is triggered due to the filter method requiring a boolean value to be returned. It would be more appropriate to utilize the forEach method in this scenario.

Answer 4

An error is triggered due to the filter method requiring a boolean value to be returned. It would be more appropriate to utilize the forEach method in this scenario.

Answer 5

Answer №3

Implement the forEach method in the following manner:

inProgressIssues = [];

issuesNotCompletedInCurrentSprint.forEach(entry => {
  if (entry.statusId === '1') {
    openIssue.push(entry);
  } else if (entry.statusId === '3') {
    inProgressIssues.push(entry);
  }
});

Answer 6

Implement the forEach method in the following manner:

inProgressIssues = [];

issuesNotCompletedInCurrentSprint.forEach(entry => {
  if (entry.statusId === '1') {
    openIssue.push(entry);
  } else if (entry.statusId === '3') {
    inProgressIssues.push(entry);
  }
});

Answer 7

Answer №4

Filter requires a boolean output as it specifies a condition for filtering and also generates a new Array.

To utilize filter, you can rewrite the code like this:

openIssue = issuesNotCompletedInCurrentSprint.filter(item => item.statusId === '1');

inProgressIssue = issuesNotCompletedInCurrentSprint.filter(item => item.statusId === '3');

Answer 8

Filter requires a boolean output as it specifies a condition for filtering and also generates a new Array.

To utilize filter, you can rewrite the code like this:

openIssue = issuesNotCompletedInCurrentSprint.filter(item => item.statusId === '1');

inProgressIssue = issuesNotCompletedInCurrentSprint.filter(item => item.statusId === '3');

Unlawful manipulation of filtering in typescript

Answer №1

Answer №2

Answer №3

Answer №4

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