Unraveling the mystery of how TypeScript automatically determines the types of

Referencing this specific question and answer, I encountered a similar issue.

Consider the following code snippet:

const myFn = <T,>(p: {
  a: (n: number) => T,
  b: (o: T) => void,
}) => {
  // ...
}


myFn({
  a: () => ({ n: 0 }), // The parameter for 'a' is disregarded
  b: o => { o.n }, // It works!
})


myFn({
  a: i => ({ n: 0 }), // The parameter 'i' is utilized here
  b: o => { o.n }, // An error occurs at 'o': Object is of type 'unknown'.ts(2571)
})

I managed to resolve this issue by introducing an additional generic:

const myFn = <T,>(p: {
  a: (n: number) => T,
  b: <U extends T /* EXTRA U generic */>(o: U) => void,
}) => {
  // ...
}

My solution was based on intuition, as I cannot pinpoint the exact reason for the error or why my fix worked :)

I believe understanding Covariant/Contrvariant/Invariant/Bivariant definitions may shed light on this.

Can you please clarify why this error occurred and why my solution proved effective?

Thank you!

UPDATE

It appears that this behavior has been rectified/updated in TypeScript 4.7

Answer №1

Commonly Used Terminology

Contextual type: This refers to the type that a code position must have based on the surrounding type it is assigned to.

Context-sensitive function: A function expression with untyped parameters whose types are derived from the contextual type.

Illustrative Example

type Fn = (s: string) => number
const fn : Fn = s => s.length 
// The above line is an example of a context-sensitive function
// The contextual type of `s` is `string`, obtained from the definition of `Fn`

Understanding Type Inference Mechanism

The TypeScript compiler does type inference in two phases:

  • First, it infers all non-context-sensitive functions.

  • In the second phase, the results of inference for type parameters (such as T) are used to infer context-sensitive functions.

If there are no inference candidates from phase 1 available for use in phase 2, you might encounter a type issue - like when T ends up being inferred as unknown.

Application to Practical Scenarios

Scenario 1:

myFn({
  a: () => ({ n: 0 }), 
  b: o => { o.n }
})

The scenario works fine because only b is context-sensitive and a is not, allowing proper inference of type T in this case.

Scenario 2:

myFn({
  a: i => ({ n: 0 }), // Parameter i is utilized
  b: o => { o.n }, // Error at o: Object is of type 'unknown'.ts(2571)
})

In this case, since both a and b are context-sensitive, they are analyzed independently in phase 2, resulting in issues related to parameter type in b.

This situation leads to the type of T becoming fixed at unknown.

Scenario 3:

const myFn = <T,>(p: {
  a: (n: number) => T,
  b: <U extends T /* EXTRA U generic */>(o: U) => void,
}) => {
  // ...
}

This workaround introduces a new type parameter U to produce separate inferences for U and T, avoiding potential issues encountered in earlier scenarios.

Alternate Suggestion

To handle complex type inference edge cases effectively, ensure that at least one function with type parameters is not context-sensitive by explicitly typing the function parameter.

For instance, explicitly typing n: number within a can resolve certain type inference challenges:

myFn({
  a: (n: number) => ({ n: 0 }),  
  b: o => { o.n },
})

Access Playground Code Here

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