update the element that acts as the divider in a web address (Angular)

Is it possible to modify the separator character used when obtaining the URL parameters with route.queryParams.subscribe? Currently, Object.keys(params) separates the parameters using "&" as the separator. Is there a way to change this to use a different character, such as "$"?

Here is the code snippet:

this.route.queryParams.subscribe(params => {
      this.keys = Object.keys(params);

}
For example, consider this URL: www.hi.com?v%2BRSC60dbdNliPmWIS8mbw%3D%3D=&uHW0Oj81Fug5ifNoPI4rGSpH5uaejSqrADBFSQhRU4fKQF3oIAXWRqtpv3TNsi3c7GDgva1P%2FozKCMFkd%2FDQEKqM1DBhmnV05psQ1n913EM5NjRNK53sEo60YxgVGky1bV%2BPB2C%2F1cG44b%2FrQPNmns7jWgQmWopQvO%2FCzWCD8o12HNQoINRzi%2FWsg9OUhoNncPl%2BU8OsJWUbKutTpW%2FiLHa4IQRvlSG59iyj6HVC2hwXwZnXVXGfDDTX3bP4Am4HQlO61CsaidcoF6mEVGSpLg%3D%3D=

In the code mentioned above, you can see that "&" is the current separator.

0 : v%2BRSC60dbdNliPmWIS8mbw%3D%3D=

&

1: uHW0Oj81Fug5ifNoPI4rGSpH5uaejSqrADBFSQhRU4fKQF3oIAXWRqtpv3TNsi3c7GDgva1P%2FozKCMFkd%2FDQEKqM1DBhmnV05psQ1n913EM5NjRNK53sEo60YxgVGky1bV%2BPB2C%2F1cG44b%2FrQPNmns7jWgQmWopQvO%2FCzWCD8o12HNQoINRzi%2FWsg9OUhoNncPl%2BU8OsJWUbKutTpW%2FiLHa4IQRvlSG59iyj6HVC2hwXwZnXVXGfDDTX3b

     P4Am4HQlO61CsaidcoF6mEVGSpLg%3D%3D=

Therefore, I am curious if there is a way to change the separator character in the URL (e.g., replace "&" with "$") and still be able to separate the parameters accordingly.

This applies to Angular.

Answer №1

Just wanted to share a helpful tip with you:

When you're working on your project, don't forget to include this in your imports:

import { ActivatedRoute } from '@angular/router';

And then, in your code, you can use the following line to get the id parameter:

const id = Number(this.activatedRoute.snapshot.paramMap.get("id"));

Let's imagine that your route looks something like this:

http://localhost:4200/identification/:id

Answer №2

Instead of complicating things, why not just use a simple method like this:

string.split("any character of your choice")

This will give you an array of substrings split at the specified

"any character of your choice"
. You can also find the index using:

string.indexOf("any character of your choice")

Then manipulate the string accordingly. You could even iterate through the string using array.forEach to find the index and then splice it at that position.

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