Upon completion of the function, ensure that no value is transmitted in TypeScript

After the first return, I am encountering an issue where the user.uid value is missing:

const functions = require(`firebase-functions`);
exports.createNewUser = functions.auth.user().onCreate((user: { uid: string; }) => {

    const newUserWallet: UserWallet = new UserWallet(user.uid);
    const rootUserWallet = admin.database().ref(`/Users/UserWallet/${user.uid}`); 
    return rootUserWallet.set(newUserWallet).then(() => {
        const newUserSettings: UserSettings = new UserSettings(user.uid);
        const rootUserSettings = admin.database().ref(`/Users/UserSettings/${user.uid}`);   
        return rootUserSettings.set(newUserSettings);
    })
    })

I have tried sending the value like this: .then((user.uid) => { or this: .then(user.uid => {, but it results in an error:

Argument of type 'string' is not assignable to parameter of type '((value: void) => void | PromiseLike<void>) | null | undefined'.ts(2345)

How can I pass this value correctly? This concerns a Firebase Function triggered upon the user creation event using TypeScript.

javascripttypescriptfirebasefunction

Answer №1

Uncertain about your intention behind the { uid: string; } section. It doesn't seem to match the structure of the user object.

However, a more efficient approach would be assigning user.uid to a constant and then utilizing it within the function. For instance:

module.exports = functions.auth.user().onCreate(user => {
  const uid = user.uid;
  // Would it make sense to simplify 'user.uid' to just 'uid' throughout the code?
})

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