Using an alias to call a function defined in a separate module in TypeScript

The following code snippet is from the v4.js file located inside the uuid folder within Angular's node_modules:

var rng = require('./lib/rng');
var bytesToUuid = require('./lib/bytesToUuid');

function v4(options, buf, offset) {
  var i = buf && offset || 0;

  if (typeof(options) == 'string') {
    buf = options == 'binary' ? new Array(16) : null;
    options = null;
  }
  options = options || {};

  var rnds = options.random || (options.rng || rng)();

  // Setting bits for version and `clock_seq_hi_and_reserved` as per 4.4
  rnds[6] = (rnds[6] & 0x0f) | 0x40;
  rnds[8] = (rnds[8] & 0x3f) | 0x80;

  // Copying bytes to buffer if provided
  if (buf) {
    for (var ii = 0; ii < 16; ++ii) {
      buf[i + ii] = rnds[ii];
    }
  }

  return buf || bytesToUuid(rnds);
}

module.exports = v4;

To import the v4 function, I use the statement:

import { v4 as uuid } from 'uuid';

I recently discovered that there are two ways to call the v4 function:

You can either use:

uuid.v4();

Or simply:

uuid();

It might be surprising how uuid() still calls the v4 function.

Answer №1

The behavior described is not limited to TypeScript but rather a result of how exports are handled in the specific package linked here.

In CommonJS modules, default and * exports are not differentiated, leading to named exports being typically exported as properties of module.exports. Currently, v4 functions as a default export, although this could change in future versions of the package:

const uuid = require('uuid');
uuid === uuid.v4;

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