Using string manipulation to eliminate the final instance of a specific character """

Can someone assist me with a situation where I need to replace the last quotation mark in a string if there is an odd number of quotation marks? I tried implementing a solution but it doesn't seem to work. Here's my code:

const input = `"hello,"sai,sur",ya,teja`;
let output = "";
if(evenOrOdd(input.split(`"`) == "even")){
 //Here the last occurrence which needed to be replaced with empty string
 input[input.split(`"`).lastIndexOf(`"`)] = "";
 console.log(input);
  output = input.replace(/"([^"]+)"/g, (_, g) => g.replace(',', '-'))
}else{
 output = input.replace(/"([^"]+)"/g, (_, g) => g.replace(',', '-'))
}


console.log(output);

function evenOrOdd(number){
//check if the number is even
if(number % 2 == 0) {
    console.log("The number is even.");
    
    return "even";
}

// if the number is odd
else {
    console.log("The number is odd.");
    return "odd";
   }
}

Thanks in advance :)

angulartypescript

Answer №1

Here is a different approach:

const text = `"hello,"sai,sur",ya,teja`;

let result = "";
let lastPosition = null;

if (checkOddOccurrences(text.split(`"`).length - 1) === "odd") {
  //Identifying the position of the last occurrence to be removed
  lastPosition = text.lastIndexOf(`"`)
  result = text.substring(0, lastPosition) + text.substring(lastPosition + 1)
}

console.log(result);

function checkOddOccurrences(count) {
  if (count % 2 == 0) {
    console.log("The count is even.");
    return "even";
  } else {
    console.log("The count is odd.");
    return "odd";
  }
}

When using the checkOddOccurrences function, pass in the number of occurrences. If the result is "even," no further action is needed. Only when it's "odd," we want to remove the last occurrence by its index in the string. Using Regex for replacement may not be necessary in this case.

Answer №2

To make a replacement, follow these steps:

const text = `"hello,"jai,jon",yes,jill`;
const position = text.lastIndexOf('"');
const updatedText = text.substr(0, position) + text.substr(position+1)


console.log(updatedText);

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