Using the original type's keys to index a mapped type

I am currently developing a function that is responsible for parsing a CSV file and returning an array of objects with specified types. Here is a snippet of the code:

type KeyToTransformerLookup<T> = {
  [K in keyof T as T[K] extends string ? never : K]: (
    stringValue: string
  ) => T[K];
};

export default function csvToArray<T>(
  csv: string,
  keys: Array<keyof T>,
  keyToTransformerLookup: KeyToTransformerLookup<T>,
  ignoreFirstLine = false
): T[] {
  const rows = csv.split(/\n(?=.)/);

  if (ignoreFirstLine) {
    rows.shift();
  }

  return rows.map((row) => {
    const values = row.split(/(?!\B"[^"]*),(?![^"]*"\B)/g);

    const rowObject: Record<any, any> = {};

    keys.forEach((key, index) => {
      const stringValue = values[index];

      if (key in keyToTransformerLookup) {
        rowObject[key] = keyToTransformerLookup[key](stringValue);
        return;
      }

      rowObject[key] = stringValue;
    });

    return rowObject as T;
  });
}
Type 'keyof T' cannot be used to index type 'KeyToTransformerLookup<T>'.

The issue arises because after mapping K in keyof T, the resulting type is no longer a subset of keyof T. This can be frustrating as I am not modifying the keys themselves, but simply checking their existence in keyToTransformerLookup. Therefore, I am looking for a way to properly index keyToTransformerLookup in order to satisfy TypeScript.

Answer №1

One limitation of TypeScript is that the narrowing via the 'in' operator currently only affects the object being checked and not the key itself. There is a feature request to add support for narrowing the key as well, but it has not been implemented yet.

If you need to work around this limitation, you can use type assertions or create custom type guard functions. However, it's important to note that such narrowing is technically unsafe because TypeScript object types are open and extendible, leading to potential runtime errors due to excess properties.


To handle this limitation until TypeScript adds proper support, consider using type assertions or creating custom type guards to ensure your code behaves as expected despite the constraints of the 'in' operator.

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