When setting "noImplicitAny": true in TypeScript, you may encounter the following errors:
Parameter 'x' implicitly has an 'any' type
This error can occur with the code snippet:
.do(x => console.log(x));
Another error you might see is:
',' expected
when using:
.do(x: any => console.log(x));
Through my exploration, I discovered the proper method for defining a type for the parameter is by including parentheses:
.do((x: any) => console.log(x));
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