Using Typescript generics to deduce the type from the second parameter for utilization in the first slot

Here is the code snippet I'm working with:

export type Subscribe<T extends object> = <U>(
  listener: (slice: U) => void,
  selector: (state: T) => U,
) => void

// The actual implementation is not relevant
const subscribe = {} as Subscribe<{ value: number }>

subscribe(
  (value) => value * 2, // TypeScript error: object is of type unknown
  (state) => state.value
)

It seems that it's challenging to infer types in this manner using TypeScript.

However, when I switch the order of parameters, it works perfectly:

export type Subscribe<T extends object> = <U>(
  selector: (state: T) => U,
  listener: (slice: U) => void,
) => void

const subscribe = {} as Subscribe<{ value: number }>

subscribe(
  (state) => state.value,
  (value) => value * 2 // No errors now! Number type is inferred correctly
)

I'd like selector to be the second parameter for optional purposes. Please inform me if this is unattainable or if you have a solution.

Answer №1

Here's an illustration to consider:

const register = <
    U extends Record<PropertyKey, unknown>,
    OutputValue,
    >(
        audience: (data: OutputValue) => void,
        converter: (input: U) => OutputValue,
) => {}

register(
    (result) => result * 2,
    (input: { number: number }) => input.number
)

Playgroud

I believe you don't necessarily need a distinct type for this scenario. All generics can be deduced at the function level.

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