Using TypeScript to set Object.prototype by utilizing the spread operator

Question

Using TypeScript to set Object.prototype by utilizing the spread operator

One efficient technique involves using the spread operator to quickly combine properties from multiple objects into a single object.

However, is there an optimized and concise method for establishing the prototype of an object using the spread operator?

My current approach is:

const result = Object.assign(Object.create(EmailCampaign.prototype), properties)

. . . this code merges properties retrieved from a database query into an object with the EmailCampaign prototype. Is it possible to set the object's prototype using the spread operator?

Here is one potential solution:

const result = Object.setPrototypeOf({...properties}, EmailCampaign.prototype);

. . however, it is not recommended for performance reasons to adjust an object's prototype after creation. I am exploring alternative options, if any are available.

javascript typescript

Answer 1

Answer №1

For optimal performance and correctness, utilizing Object.assign along with Object.create is the recommended approach. It is advisable to implement this method. To streamline the process, you can create a helper function that combines both techniques.

Although not excessively slow, it should be noted that employing Object.setPrototypeOf on an object literal is unnecessary if the object has not been referenced elsewhere.

Is there a way to establish the prototype of an object using the spread operator?

If you are willing to use a feature that has been officially deprecated, you can utilize the __proto__ property within an object initializer:

const result = {__proto__: EmailCampaign.prototype, ...properties};

In conclusion, while this method is feasible, it is strongly advised against its usage.

Answer 2

For optimal performance and correctness, utilizing Object.assign along with Object.create is the recommended approach. It is advisable to implement this method. To streamline the process, you can create a helper function that combines both techniques.

Although not excessively slow, it should be noted that employing Object.setPrototypeOf on an object literal is unnecessary if the object has not been referenced elsewhere.

Is there a way to establish the prototype of an object using the spread operator?

If you are willing to use a feature that has been officially deprecated, you can utilize the __proto__ property within an object initializer:

const result = {__proto__: EmailCampaign.prototype, ...properties};

In conclusion, while this method is feasible, it is strongly advised against its usage.

Using TypeScript to set Object.prototype by utilizing the spread operator

Answer №1

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