Using TypeScript's Non-Null Assertion Operators in combination with square brackets []

One way to assert that an object has a certain property is by using the `!.` syntax as shown below:

type Person = {
  name: string;
  age: number;
  gender?: string;
}

const myPerson: Person = {
  name: 'John Cena',
  age: 123,
  gender: 'sth'
}

const myFunction = (person: Person) => {
  checkIfPersonHasGender(person);
  return person!.gender;
}

But how do we apply this for properties with keys in quotations like the example below? :

type Person = {
  name: string;
  age: number;
  "my-gender"?: string;
}

I attempted to use

myPerson!.["my-gender"]
, however TypeScript returned an error saying Identifier expected.

Answer №1

If you have full confidence that `myPerson["my-gender"]` is always defined, TypeScript offers a convenient solution through its type assertion feature. By using type assertions, you can inform TypeScript that `myPerson["my-gender"]` will never be `undefined`.

Syntax for Type Assertion

// without type assertion
myPerson["my-gender"]; // type 👉 string | undefined

// default type assertion syntax
myPerson["my-gender"] as string; // type 👉 string

// angle-bracket type assertion syntax
<string> myPerson["my-gender"]; // type 👉 string

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