Utilize restrictions (type/interface) on data types

When working with TypeScript, I am creating a type that consists of unions of other types:

type A = B | C | D // ...

One important requirement is that I want to ensure at compile time that B, C, D, and so on, have the structure of a generic template to ensure correctness in the composite. This means I need some kind of interface for types or a type for a type.

For example, B should "implement" Template:

type Template = { x: string; y: { [key: string]: any } };
type B = {x: "test", y: {test2: number}}

What would be the best approach to solve this issue?

Answer №1

UPDATE

Following @jcalz's suggestion, passing a union to a generic type can help validate if it meets the constraint. Find a demo on the Playground.

type Template = { x: string; y: { [key: string]: any } };
type B = { x: "B", y: { test2: number } }
type C = { x: "C", y: { test2: number } }
type D = { x: "C", y: { test2: number } }
type E = { x: 5 }

type Check<U, T extends U> = T

// @ts-expect-error
type AError1 = Check<Template, B | C | E>

// @ts-expect-error
type AError2 = Check<Template, B | C | D | E>

type A = Check<Template, B | C | D>

Integrating generics can be useful, although it may become lengthy when dealing with more than 10 possible types in a union. View a sample on the Playground.

type Template = { x: string; y: { [key: string]: any } };
type B = {x: "B", y: {test2: number}}
type C = {x: "C", y: {test2: number}}
type D = {x: "C", y: {test2: number}}
type  E = {x: 5}

type MakeUnion<TBase, T1 extends TBase, T2 extends TBase, T3 extends TBase = never, T4 extends TBase = never, T5 extends TBase = never> = T1 | T2 | T3 | T4 | T5

// @ts-expect-error
type AError1 = MakeUnion<Template, B, C, E>

// @ts-expect-error
type AError2 = MakeUnion<Template, B, C, D, E>

type A = MakeUnion<Template, B, C, D>

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