"Utilize the handle property of a component when interacting with the window.onclick

In my component, I have a property called enableButtons which is set to true when I click on an ion-menu label. However, I want this property to revert to false if I click anywhere else. Here's the code I tried:

export class ProfilePage implements OnInit {
  enableButtons: boolean;

  constructor(private router: Router,private menu: MenuController) {
    this.enableButtons= false;
    
    window.onclick = function(event) {
      if(this.enableButtons){  
        this.enableButtons = false;
      }
    }
  }

  async presentModalEliminaItems() {
    this.menu.close();  
    this.enableButtons = true;      
  }

The issue here is that "this" in the window.onclick function refers to Window type instead of ProfilePage type. How can I resolve this?

SOLVED: I resolved it by using Angular's Renderer2 class instead of window.onclick:

@ViewChild('aEliminaVideo') toggleButton: ElementRef;

  this.renderer.listen('window', 'click',(e:Event)=>{
    if(e.target!==this.toggleButton.nativeElement && this.enableButtons == true){
      this.enableButtons = false;
    }
  });

Answer №1

In order to resolve the issue of `undefined` in this code snippet, it is recommended to reposition your code within the `ngOnInit(){}` function. This will address the runtime issue between `Constructor` and `OnInit`. Another approach is to use the `non null assertion operator` by adding a `!` mark to your declared properties. This signifies to TypeScript that you are aware your properties will have values at runtime, allowing you to bypass strict checking. For example: `enableButtons!: boolean;

Answer №2

Start by setting up the attribute in your declaration:

export class ProfilePage implements OnInit {
  allowAccess = true;

  ...
}

The system will automatically determine that it is a boolean based on the value you assign.

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