Is there a way to utilize keyof in defining function parameters based on an optional field within an Object, while also including a default value?
interface test {
example?: {
choice1: string,
choice2: string
}
}
function sample(param: keyof test["example"] = "choice1") ...
Encountering the error
Type 'string' is not assignable to type 'never'example.
To eliminate the chance of encountering undefined, you can utilize the NonNullable method:
function func(option: keyof NonNullable<foo["bar"]> = "opt1")
It's important to note that this approach will also remove the possibility of null, which may not always be desirable. Another alternative is to employ Exclude, a more verbose but versatile option:
function func(option: keyof Exclude<foo["bar"], undefined> = "opt1")
For further information regarding these utility types, refer to this page: https://www.typescriptlang.org/docs/handbook/utility-types.html
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