Every time I attempt this, it only displays once and seems to be incorrect. Is there a way to resolve the issue?
function myFunc() {
var increment = (function() {
var i = 0;
return function() {
i++;
return i;
};
})();
alert(`myFunc has been called ${increment()} times`);
}
Every time you invoke my function, it will redefine the increment function, so don't expect it to output anything other than 1. The issue is that increment gets redefined with each call to myFunc
The solution is as follows:
var i = 0;
function myFunc() {
var increment = (function() {
return function() {
i++;
return i;
};
})();
alert(`calling myFunc ${increment()} times`);
}
Now i will maintain its value across calls to myFunc. It must be declared outside of myFunc. Alternatively, you can move the entire function outside of myFunc.
var increment = (function() {
var i = 0;
return function() {
i++;
return i;
};
})();
function myFunc() {
alert(`calling myFunc ${increment()} times`);
}
Now it functions correctly:
console.log(increment()); // outputs 1
console.log(increment()); // outputs 2
One issue arises when a variable exits its scope and gets destroyed. Upon the next value call, it will be recreated with its initial value. In this case, the variable i is scoped within the increment function, which in turn is within the scope of myFunc. This means that each time myFunc is executed, the closure is destroyed and then created again.
An illustrative example showcases how i is hoisted to the scope of
myFunc</code, with the <code>incrementfunction myFunc() {
console.log('running myFunc');
var i = 0;
console.log('assigning i to ' + i);
function increment() {
console.log('incrementing');
i++;
};
increment();
increment();
console.log(`calling myFunc ${i} times`);
}
myFunc();It can be observed that i retains its state across invocations of the increment function. Whenever we call myFunc repeatedly, we witness the destruction and recreation of i each time myFunc is invoked.
function myFunc() {
console.log('running myFunc');
var i = 0;
console.log('assigning i to ' + i);
function increment() {
console.log('incrementing');
i++;
}
increment();
increment();
console.log(`calling myFunc ${i} times`);
}
myFunc();
myFunc();If we lift i outside the scope of myFunc, we notice that its value persists across calls to myFunc.
var i = 0;
console.log('assigning i to ' + i);
function myFunc() {
console.log('running myFunc');
function increment() {
console.log('incrementing');
i++;
}
increment();
console.log(`calling myFunc ${i} times`);
}
myFunc();
myFunc();Works perfectly for my needs.
def double(num):
result = num * 2
return result
print(double(5))
print(double(10))
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