Utilizing dynamic arguments in TypeScript to recycle types

Can I accomplish this with TypeScript? Here is the source code I currently have:

interface FormStore<T> {
  type: T;
}

interface Form<T> extends FormStore<T> {
  email: T;
  phone: T;
  password: T;
}

interface FormState<R> {
  form: Form<string>;
  validate: Form<boolean>;
}

I am looking to reuse the type FormState<R> and create a new one with a different argument. Essentially, replacing Form with R:

// This example doesn't work, just for demonstration purposes
interface FormState<R> {
  form: R<string>;
  validate: R<boolean>;
}

// another file
FormState<CustomForm>

Answer №1

Based on your initial statement, this is the best solution I can offer at the moment. If you do not specify a default type parameter for FormStore and Form, you will need to explicitly define

type FormStateF = FormState<Form<unknown>>;
, which can be cumbersome.

interface FormStore<T = unknown> {
  type: T;
}

interface Form<T = unknown> extends FormStore<T> {
  email: T;
  phone: T;
  password: T;
}

interface FormState<R> {
  form: { [x in keyof R]: string };
  validate: { [x in keyof R]: boolean };
}

type FormStateF = FormState<Form>;

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