export class SearchResult {
id: string;
constructor(obj?: any) {
this.id = obj && obj.id || null;
}
}
Can someone explain to me the meaning of obj && obj.id || null? I'm confused by this syntax.
export class SearchResult {
id: string;
constructor(obj?: any) {
this.id = obj && obj.id || null;
}
}
Can someone explain to me the meaning of obj && obj.id || null? I'm confused by this syntax.
Although your code is written in Typescript, the topic of this question revolves around JavaScript.
When it comes to JavaScript:
true && expression
will result in the evaluation of the expression.
On the other hand:
false && expression
this will return false, causing the expression to not be executed.
Therefore, in your constructor, if obj is truthy (for example, not null or undefined), the expression will be executed, allowing you to access obj.id and assign its value to this.id. If obj is not truthy, it will result in false, and this.id will be assigned a null value.
This approach is commonly used in React, you can find an example here.
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