Verify if two arrays of objects demonstrate unique distinctions within the latter

Question

Verify if two arrays of objects demonstrate unique distinctions within the latter

My task involves working with two arrays of objects, each containing a unique property id that corresponds to a filterID retrieved from a dynamoDb database. The goal is to extract the objects that have different values associated with the same id.

const firstArray = [
    {
        1234: "food"
    },
    {
        5678: "animal"
    },
    {
        4444: "car"
    }
]

const secondArray = [
    {
        1234: "food"
    },
    {
        5678: "bread"
    },
    {
        4444: "car"
    }
]

const findDifferentObjects = () => firstArray.filter(object1 => {
    return !secondArray.some(object2 => {
        return object1 === object2
    })
})
 console.log(findDifferentObjects())

Basically, what I'm aiming for is to obtain:

const different = [
    {
        5678: "animal"
    },
]

I have experimented with different approaches, similar to the example provided, but haven't been successful yet.

javascript arrays typescript object

Answer 1

Answer №1

Almost there, just remember to extract the object key and then compare the values, rather than comparing the object references directly.

const filterObjects = () => data.filter(obj1 => {
    return !anotherArray.some(obj2 => {
        const key = Object.keys(obj1)[0];
        return obj1[key] == obj2[key];
    })
})
console.log(filterObjects())

Answer 2

Almost there, just remember to extract the object key and then compare the values, rather than comparing the object references directly.

const filterObjects = () => data.filter(obj1 => {
    return !anotherArray.some(obj2 => {
        const key = Object.keys(obj1)[0];
        return obj1[key] == obj2[key];
    })
})
console.log(filterObjects())

Answer 3

Answer №2

try using the following code snippet:

const filterObjects = () =>
  data.filter((obj1) => {
    return !temp.some((obj2) => {
      return JSON.stringify(obj1) === JSON.stringify(obj2);
   });
  });
console.log(filterObjects());

When comparing objects, remember they are stored in different locations in memory. To properly compare them, compare their properties or convert them to strings and then compare.

Answer 4

try using the following code snippet:

const filterObjects = () =>
  data.filter((obj1) => {
    return !temp.some((obj2) => {
      return JSON.stringify(obj1) === JSON.stringify(obj2);
   });
  });
console.log(filterObjects());

When comparing objects, remember they are stored in different locations in memory. To properly compare them, compare their properties or convert them to strings and then compare.

Answer 5

Answer №3

let numbers = [
    {
        1234: "fruit"
    },
    {
        5678: "pet"
    },
    {
        4444: "vehicle"
    }
]

let words = [
    {
        1234: "fruit"
    },
    {
        5678: "dog"
    },
    {
        4444: "car"
    }
]

const findDifferentItems = (arr1, arr2) => {
   let result = arr1.filter(item => {
     return Object.keys(item).some(key => {
       return arr2.some(compare => {
         return (compare[key] && item[key] !== compare[key]);
       });       
     })
   });
   return result;  
}

const updatedItems = findDifferentItems(numbers, words);
console.log(updatedItems);

Answer 6

let numbers = [
    {
        1234: "fruit"
    },
    {
        5678: "pet"
    },
    {
        4444: "vehicle"
    }
]

let words = [
    {
        1234: "fruit"
    },
    {
        5678: "dog"
    },
    {
        4444: "car"
    }
]

const findDifferentItems = (arr1, arr2) => {
   let result = arr1.filter(item => {
     return Object.keys(item).some(key => {
       return arr2.some(compare => {
         return (compare[key] && item[key] !== compare[key]);
       });       
     })
   });
   return result;  
}

const updatedItems = findDifferentItems(numbers, words);
console.log(updatedItems);

Verify if two arrays of objects demonstrate unique distinctions within the latter

Answer №1

Answer №2

Answer №3

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