Ways to eliminate a particular nested item from an array consisting of arrays

Question

Ways to eliminate a particular nested item from an array consisting of arrays

Looking to remove an item from an array of objects?

[
  {
    "category": "CC",
    "paymentOptions": [
      {
        "payCode": "v",
        "description": "Visa"
      },
      {
        "payCode": "m",
        "description": "Master"
      }
    ]
  },
  {
    "category": "PayPal",
    "paymentOptions": [
      {
        "payCode": "PY",
        "description": "Paypal"
      }
    ]
  }
]

The goal is to remove the specific section from the array of objects provided above:

{
  "payCode": "m",
  "description": "Master"
}

After removing the specified section, the updated array should look like this:

[
  {
    "category": "CC",
    "paymentOptions": [
      {
        "payCode": "v",
        "description": "Visa"
      }
    ]
  },
  {
    "category": "PayPal",
    "paymentOptions": [
      {
        "payCode": "PY",
        "description": "Paypal"
      }
    ]
  }
]

A previous attempt using the code below did not yield the desired outcome:

this.payments.filter(x => x.paymentOptions.filter(x => x.description.toLowerCase() !="Master"))

How can I achieve this? The expected output should match the example after removal of the specific object.

arrays typescript multidimensional-array

Answer 1

Answer №1

If you want to eliminate the element with a description of "master" from the paymentOptions array for each item in the payments array.

The statement
```
x.description.toLowerCase() != "Master"
```
will never evaluate to true.
Utilize the Array.map() method to loop through and modify the paymentOptions array for each element.

let result = this.payments.map(x => ({
  ...x,
  paymentOptions: x.paymentOptions.filter(y => y.description.toLowerCase() != "master")
}));

See Demo @ TypeScript Playground

Answer 2

If you want to eliminate the element with a description of "master" from the paymentOptions array for each item in the payments array.

The statement
```
x.description.toLowerCase() != "Master"
```
will never evaluate to true.
Utilize the Array.map() method to loop through and modify the paymentOptions array for each element.

let result = this.payments.map(x => ({
  ...x,
  paymentOptions: x.paymentOptions.filter(y => y.description.toLowerCase() != "master")
}));

See Demo @ TypeScript Playground

Answer 3

Answer №2

In case you no longer require the initial array, you have the option to utilize forEach method:

this.payments.forEach(x => {
  paymentOptions: x.paymentOptions
           .filter(y => y.description.toLowerCase() != "master")
});

Answer 4

In case you no longer require the initial array, you have the option to utilize forEach method:

this.payments.forEach(x => {
  paymentOptions: x.paymentOptions
           .filter(y => y.description.toLowerCase() != "master")
});

Answer 5

Answer №3

Your code contains several errors that need to be addressed:

The result of the first filter call is not stored. Remember, 'filter' returns a new array and does not modify the original one.
Using a filter call as a test for another filter call will likely not work as expected. A condition should be provided, and the inner filter's result should be stored.
The comparison using 'toLowerCase' with 'Master' will always return true due to case sensitivity.

You can improve your code by utilizing a combination of 'map' and 'filter' like this:

this.payments = [
  {
    "category": "CC",
    "paymentOptions": [
        {
            "payCode": "v",
            "description": "Visa"
        },
        {
            "payCode": "m",
            "description": "Master"
        }
    ]
  },
  {
    "category": "PayPal",
    "paymentOptions": [
        {
            "payCode": "PY",
            "description": "Paypal"
        }
    ]
  }
];

var result = this.payments.map(a => {
  a.paymentOptions = a.paymentOptions.filter( x => x.description.toLowerCase() != 'master' );
  return a;
});

console.log(result);

Answer 6

Your code contains several errors that need to be addressed:

The result of the first filter call is not stored. Remember, 'filter' returns a new array and does not modify the original one.
Using a filter call as a test for another filter call will likely not work as expected. A condition should be provided, and the inner filter's result should be stored.
The comparison using 'toLowerCase' with 'Master' will always return true due to case sensitivity.

You can improve your code by utilizing a combination of 'map' and 'filter' like this:

this.payments = [
  {
    "category": "CC",
    "paymentOptions": [
        {
            "payCode": "v",
            "description": "Visa"
        },
        {
            "payCode": "m",
            "description": "Master"
        }
    ]
  },
  {
    "category": "PayPal",
    "paymentOptions": [
        {
            "payCode": "PY",
            "description": "Paypal"
        }
    ]
  }
];

var result = this.payments.map(a => {
  a.paymentOptions = a.paymentOptions.filter( x => x.description.toLowerCase() != 'master' );
  return a;
});

console.log(result);

Answer 7

Answer №4

One recurring suggestion in all the answers is to utilize the array.filter(…) method.

However, there exist numerous alternative approaches, one of which involves actively seeking out and eliminating the unwanted items from the original array instead of simply creating a new array without them. Notably, this method alters the original data.

interface Item {
  category: string
  paymentOptions: Array<{
    payCode: string
    description: string
  }>
}

function removePaymentOptions(category: string, payCode: string, items: Item[]): void {
  // Identify items that need to be updated
  const itemsToUpdate = items.filter((item) => item.category === category)

  // Locate and remove undesired payment options in each item
  for (const item of itemsToUpdate) {
    const optionIndex = item.paymentOptions.findIndex((option) => option.payCode === payCode)

    // If the payment option exists, eliminate it from the item
    if (optionIndex !== -1) {
      item.paymentOptions.splice(optionIndex, 1)
    }
  }
}

const items = /* your array */

removePaymentOptions('CC', 'm', items)

// The `items` array has now been updated to exclude the undesirable payment options

Answer 8

One recurring suggestion in all the answers is to utilize the array.filter(…) method.

However, there exist numerous alternative approaches, one of which involves actively seeking out and eliminating the unwanted items from the original array instead of simply creating a new array without them. Notably, this method alters the original data.

interface Item {
  category: string
  paymentOptions: Array<{
    payCode: string
    description: string
  }>
}

function removePaymentOptions(category: string, payCode: string, items: Item[]): void {
  // Identify items that need to be updated
  const itemsToUpdate = items.filter((item) => item.category === category)

  // Locate and remove undesired payment options in each item
  for (const item of itemsToUpdate) {
    const optionIndex = item.paymentOptions.findIndex((option) => option.payCode === payCode)

    // If the payment option exists, eliminate it from the item
    if (optionIndex !== -1) {
      item.paymentOptions.splice(optionIndex, 1)
    }
  }
}

const items = /* your array */

removePaymentOptions('CC', 'm', items)

// The `items` array has now been updated to exclude the undesirable payment options

Ways to eliminate a particular nested item from an array consisting of arrays

Answer №1

Answer №2

Answer №3

Answer №4

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