Ways to merge two distinct arrays [Angular and Typescript]

I am faced with a task where I need to merge two array lists in order to create a new array list that contains all the values associated with a common UUID in both lists. The final list should include all the values linked to the UUID in each of the original array lists.

List 1:

[
  {
  "uuid":"01",
  "plan" : "aaaa",
  "other_details":"xxxxxx"
  },
  {
    "uuid" : "02",
    "plan" : "bbbb",
    "other_details":"yyyyyyy"
  },
  {
    "uuid" : "03",
    "plan" : "cccc",
    "other_details":"zzzzzz"
  },
  {
    "uuid" : "04",
    "plan" : "dddd",
    "other_details":"uuuuuu"
  }
]

List 2:

[
  {
  "uuid":"01",
  "office" : "India",
  "status":"running"
  },
  {
    "uuid" : "02",
    "office" : "USA",
    "status":"running"
  },
  {
    "uuid" : "03",
    "office" : "Germany",
    "status":"running"
  },
  {
    "uuid" : "04",
    "office" : "Australia",
    "status":"shutdown"
  }
]

The goal is to combine the two array lists using the unique "UUID" value. The resulting array should appear as follows:

[
  {
  "uuid":"01",
  "plan" : "aaaa",
  "other_details":"xxxxxx",
    "office" : "India",
  "status":"running"
  },
  {
    "uuid" : "02",
    "plan" : "bbbb",
    "other_details":"yyyyyyy",
    "office" : "USA",
    "status":"running"
  },
  {
    "uuid" : "03",
    "plan" : "cccc",
    "other_details":"zzzzzz",
    "office" : "Germany",
    "status":"running"
  },
  {
    "uuid" : "04",
    "plan" : "dddd",
    "other_details":"uuuuuu",
    "office" : "Australia",
    "status":"shutdown"
  }
]

Is it possible to iterate through the array like this?

   for(listItem1 in arraylist1){  
     for (listitem2 in arraylist2){
    if(listItem1.uuid=== listItem2.uuid){
listItem = ""
}
    }
    }

How can I create the third array list and store the items in it?

Answer №1

If you want to streamline this code, consider using the spread operator in ECMAScript.

By utilizing the spread operator, we can merge two lists like so: const mergedList = listOne.map(listItem1 => ({...listItem1, ...listTwo.find(listItem2 => listItem2.id === listItem1.id)}))

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