Ways to store a component in cache once its route is triggered

There are 3 components in my project: 1 parent and 2 child components with router outlet. The child component becomes active whenever its route is called, sharing data using a service.

Both of these child components have complex views.

When switching between these two routes, it takes a long time to render the view (I have used some bootstrap UI, ngbootstrap, and other libraries).

The data remains unchanged between these two child components, only the view part changes which slows down the process.

Is there a way to cache these components once they are called to improve performance? Any suggestions would be greatly appreciated. Thank you.

javascriptangulartypescriptcachingangular-ui-router

Answer №1

That's an interesting question. I haven't personally tried it, but one way to accomplish that is by utilizing RouteReuseStrategy. Although you haven't given a specific example, typically you would need to use the following methods:

  • shouldAttach - returns true/false to decide if the retrieve method should be invoked to retrieve the component instead of creating it anew.
  • retrieve - returns RouteHandle or null when called, providing a chance to retrieve a cached component as a DetachedRouteHandle.
  • shouldDetach - returns true/false to determine if the store method should be invoked.
  • store - returns nothing but takes in a detachedTree that can be saved (cached) to retain your component's state and later retrieve it with the retrieve method.

It might seem complicated, but it's actually simpler than replacing the router-outlet with a custom alternative. This article explains it well and offers a helpful example. I hope that clears things up.

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