The playground demo
The diff:
A:
function<T extends { status: number }> () {}
B:
function<T = any> () {}
the B
does not have access to T's property, while the A
function only accesses T's status
.
Thank you
The playground demo
The diff:
A:
function<T extends { status: number }> () {}
B:
function<T = any> () {}
the B
does not have access to T's property, while the A
function only accesses T's status
.
Thank you
The functionality is operating precisely as intended. Attempting to retrieve the status
attribute from a variable of type T
is not feasible unless you can confirm that T
possesses a status
property.
<T extends { status: number }>
signifies that irrespective of the explicit value of T
, it will always contain a status
property.
<T = any>
implies that T
has the potential to be anything. How would you go about extracting the status
attribute from a boolean
, for example? This would lead to a runtime error. Therefore, typescript generates a compile-time error to prevent such actions.
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