Here is a basic class example:
export class Logger {
constructor(private name: string) {}
debug(...args: any[]) {
console.debug(...args)
}
log(...args: any[]) {
console.log(...args)
}
}
Despite being able to pass anything to console.log and console.debug, I encounter the following errors:
.apply(args)does work, but then what is the purpose of using the...argssyntax?This was tested using TypeScript version 2.2.2.
console.log is typically defined as follows:
log(message?: any, ...optionalParams: any[]): void;
If you're looking to make a change, consider using this alternative approach:
export class Logger {
constructor(private name: string) {}
debug(msg?: any, ...args: any[]) {
console.debug(msg, ...args)
}
log(msg?: any, ...args: any[]) {
console.log(msg, ...args)
}
}
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