What does the generic argument on the right side of the statement indicate in TypeScript?

Can you identify the name of <R> in TypeScript? It appears to be a type that is derived from the passed argument, with no clear documentation available. The generic portion only delves into the details of the left side <S>.

type F<S> = <R>(fn: (s: S) => R) =>  R;
    

Answer №1

The specific name of the inner generic is not clearly defined, but it represents the type of the function to which you pass the callback fn. Let's gain a better understanding by actually implementing this type:

// Updated as `<R>(fn: (s: number) => R)`
const exampleFunction: F<number> = callbackFn => callbackFn(1);
// num is a number
const result1 = exampleFunction<string>(num => num.toString());
// error due to `num` being a number without `length`
const result2 = exampleFunction<string>(num => num.length);
// returning a boolean instead of a string results in an error
const result3 = exampleFunction<string>(num => !!num);

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