What is the best way to allow the browser to either download a file or open it in a new tab based on what is feasible? (while maintaining the actual file

Currently in my web application, which utilizes Angular for the front-end and .Net Core for the back-end, there is a page where users can click on server-side stored files. The desired behavior is for the file to open directly in a new tab if the browser allows (e.g., text, images, PDF). If not permitted by the browser, the file should be downloaded instead.

The code snippet from my Angular implementation looks like this:

openFile(fileId: string, name: string) {
    this.httpClient.get('Attachments/Download/' + fileId, { responseType: 'arraybuffer', headers: { 'Content-Type': 'text/plain' }, observe: 'body' }).subscribe(file => {
        if (!file) {
            console.error("file not found.");
            return;
        }

        this.http.get<string>('File/MimeType/' + encodeURIComponent(name)).subscribe(mimetype => {
            if (!mimetype || mimetype === '') {
                console.error("mimetype not found.");
            } else {
                const blob = new Blob([file], { type: mimetype });
                const url = window.URL.createObjectURL(blob);
                window.open(url, '_blank');
            }
        });
    });
}

Although it functions correctly, the use of window.URL.createObjectURL(blob) leads to file names being replaced with an ID format (e.g.,

blob:http://my-site/8b92c1b8-72e9-461c-b66c-40a65e705591
). I am aware of alternative methods such as using an <a> tag with the download attribute (which preserves the original file name but does not allow direct opening in the browser).

The goal is for the browser to determine the appropriate action whenever possible. Any suggestions or solutions are appreciated. Thank you in advance. :)

EDIT: I welcome suggestions that involve utilizing only the backend (.Net Core) as long as the file still opens in a new tab.

Answer №1

Forcing a file to "open" directly after downloading it from a web application might not be possible in the traditional sense of execution. However, there is a simpler solution that you may not have considered.

By using the code snippet window.open('https://path/to/file.extenstion', '_blank');

The file will open in a new tab for viewing or download. Depending on your browser settings, PDF files may display within the browser while other file types will prompt a download. Images will typically download as-is.

Answer №2

Quick Tip

Dealing with file downloads in different browsers can be tricky, but here's a workaround that might work for you.

Customizing Filename

Instead of using a blob, consider utilizing the File object to specify the desired filename.

const downloadFile = new File([file], name, { type: mimetype }); // specify the filename using the 'name' variable

Unconventional Mimetype

In this method, setting the default mimetype as application/text prompts the browser to save the file as a .txt, then open it locally.

mimetype = "application/text"

Although the URL doesn't display the filename, the downloaded file will have the correct name.

Cleaning Up

Remember to revoke the URL post-download to maintain security and release the blob reference.

URL.revokeObjectURL(url);

Implementation Code

file = ""
name = "document.pdf"
mimetype = "application/text"
const downloadFile = new File([file], name, { type: mimetype }); 
const url = window.URL.createObjectURL(blob);
window.open(url, '_blank');
URL.revokeObjectURL(url);

Live example: https://codepen.io/w-b/pen/VwXXjdL

Additional details on the file constructor can be found here

Answer №3

After attempting to open a file (whether it be PDF, TXT, DOXC, or any other format), I found that clicking to open the file in a modal was more efficient.

If you wish to click on "open file" and have it open in a new tab, consider implementing the following method:

Be sure not to overlook the essential package: ngx-doc-viewer

  1. Create a component called show_attachment.
  2. Implement the function openFile() within the ShowAttachmentComponent.

In the show_attachment.component.ts file:

@Input path: string;
@Input minitype: string;


  isDocx(mimetype) {
    return mimetype.includes('wordprocessingml.document') || mimetype.includes('msword');
  }

  isXlsx(mimetype) {
    return mimetype.includes('spreadsheetml.sheet') || mimetype.includes('application/vnd.ms-excel') || mimetype.includes('application/excel');
  }

  isPowerPoint(mimetype) {
    return mimetype.includes('presentation') || mimetype.includes('powerpoint');
  }

  isCSV(mimetype) {
    return mimetype.includes('text/csv') || mimetype.includes('text/comma-separated-values');
  }

  isTxt(mimetype) {
    return mimetype.includes('text/plain');
  }

In the show_attachment.component.html file:

<div class="show-detail" *ngIf="getIsImage(this.mimetype)">
            <img [src]="path"/>
        </div>      
        <div class="show-detail doc-content" *ngIf="isDocx(this.mimetype) || isXlsx(data.detail.external_video_type) || isPowerPoint(this.mimetype)">
            <ngx-doc-viewer [url]="path" viewer="office" style="width:100%;height:80vh;">
            </ngx-doc-viewer>
        </div>
        <div class="show-detail other-content" *ngIf="isTxt(this.mimetype)">
            <ngx-doc-viewer [url]="path" viewer="url" style="width:100%;height:80vh;">
            </ngx-doc-viewer>
        </div>

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