What is the best way to change the number 123456789 to look like 123***789 using either typescript or

Question

What is the best way to change the number 123456789 to look like 123***789 using either typescript or

Is there a way to convert this scenario? I am working on a project where the userID needs to be displayed in a specific format. The first 3 characters/numbers and last 3 characters/numbers should be visible, while the middle part should be replaced with asterisks (*).

javascript typescript

Answer 1

Answer №1

To easily solve this problem, you can divide the text into three parts: beginning, middle, and end. Then, modify the middle section.

const alterText = (text) => {
  const startSection = text.slice(0, 3);
  const endSection = text.slice(text.length - 3, text.length);
  const middleSection = text.slice(3, text.length - 3);
  var modifiedMiddle = "";
  for (var i = 0; i < middleSet.length; i++) {
    modifiedMiddle = modifiedMiddle.concat("*");
  }
  const updatedText = startSection.concat(modifiedMiddle, endSection);
  return updatedText;
};

Answer 2

To easily solve this problem, you can divide the text into three parts: beginning, middle, and end. Then, modify the middle section.

const alterText = (text) => {
  const startSection = text.slice(0, 3);
  const endSection = text.slice(text.length - 3, text.length);
  const middleSection = text.slice(3, text.length - 3);
  var modifiedMiddle = "";
  for (var i = 0; i < middleSet.length; i++) {
    modifiedMiddle = modifiedMiddle.concat("*");
  }
  const updatedText = startSection.concat(modifiedMiddle, endSection);
  return updatedText;
};

Answer 3

Answer №2

Because JavaScript strings cannot be changed, the best approach is to create a new string altogether. One method to achieve this is by breaking down the string into individual characters and storing them in an array, as arrays are changeable. This task can be accomplished using Array.from.

Following that, you can update specific characters. In the given scenario where you need to alter a series of values to be identical, you can utilize Array.fill, which will substitute a portion of the array with a specified value.

After making these adjustments, all that remains is to merge them back into a string, a process that can be done through Array.join.

let concealCenter = (str) => Array.from(str).fill("*", 3, -3).join("");

Answer 4

Because JavaScript strings cannot be changed, the best approach is to create a new string altogether. One method to achieve this is by breaking down the string into individual characters and storing them in an array, as arrays are changeable. This task can be accomplished using Array.from.

Following that, you can update specific characters. In the given scenario where you need to alter a series of values to be identical, you can utilize Array.fill, which will substitute a portion of the array with a specified value.

After making these adjustments, all that remains is to merge them back into a string, a process that can be done through Array.join.

let concealCenter = (str) => Array.from(str).fill("*", 3, -3).join("");

Answer 5

Answer №3

Here is a simple solution:

const obscureString = (str) =>{
    let hiddenStr = ""
    let errorFlag = false
    let errorMessage = ""
    if(str != null && str !=""){
        errorFlag = false
        let firstThreeChars = str.slice(0, 3)
        let lastThreeChars = str.slice(str.length-3, str.length)
        hiddenStr = `${firstThreeChars}***${lastThreeChars}`
    }else{
        errorFlag = true
        errorMessage = "Please provide a valid string."
        return errorMessage
    }
    return hiddenStr
}

// Example of calling the function
console.log(obscureString("12345678"))

Answer 6

Here is a simple solution:

const obscureString = (str) =>{
    let hiddenStr = ""
    let errorFlag = false
    let errorMessage = ""
    if(str != null && str !=""){
        errorFlag = false
        let firstThreeChars = str.slice(0, 3)
        let lastThreeChars = str.slice(str.length-3, str.length)
        hiddenStr = `${firstThreeChars}***${lastThreeChars}`
    }else{
        errorFlag = true
        errorMessage = "Please provide a valid string."
        return errorMessage
    }
    return hiddenStr
}

// Example of calling the function
console.log(obscureString("12345678"))

What is the best way to change the number 123456789 to look like 123***789 using either typescript or

Answer №1

Answer №2

Answer №3

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