Can someone help me compare two arrays in TypeScript to see if they are identical? I'm having trouble with the current code. Here's what I have:
let props:(string|boolean)[]=['abc','def',true,false,'xyz']
let propsCopied:(string|boolean)[]=['abc','def',true,false,'xyz']
let allPropsCopied:boolean;
if(props===propsCopied){
allPropsCopied=true;
}
Here is a concise method you can use:
JSON.stringify(objects)===JSON.stringify(objectsCopied)
Alternatively, you can opt for a more comprehensive approach like this:
function areArraysEqual(x:(string|boolean)[], y:(string|boolean)[]) {
if (x === y) return true;
if (x == null || y == null) return false;
if (x.length !== y.length) return false;
// If maintaining order of elements isn't important,
// consider sorting both arrays before comparison.
// Take caution as sorting directly impacts the array,
// so it may be wise to create copies first.
for (var j = 0; j < x.length; ++j) {
if (x[j] !== y[j]) return false;
}
return true;
}
The JavaScript version of the answer in a related query:
function checkArraysEquality<T>(arr1: T[] | null, arr2: T[] | null): bool {
if (arr1 === arr2) {
return true;
}
if (arr1 == null || arr2 == null || arr1.length !== arr2.length) {
return false;
}
// If you are not concerned about the order of elements inside
// This is a loose comparison. For strict comparison, consider counting each element.
// return arr1.every(item => arr2.some(item)) && arr2.every(item => arr1.some(item));
for (let index = 0; index < arr1.length; ++index) {
if (arr1[index] !== arr2[index]) {
return false;
};
}
return true;
}
Usage in your code:
let items:(string|boolean)[]=['abc','def',true,false,'xyz']
let copiedItems:(string|boolean)[]=['abc','def',true,false,'xyz']
let areAllItemsEqual:boolean = checkArraysEquality(items, copiedItems);
I found success with the solution '
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