What is the best way to conditionally return an optional generic type from a function?

In this code snippet, we have a simple example of a function that accepts an optional generic type and an optional second parameter. If the second parameter is provided, it will return the generic type.

const helper = async <T = void>(
  config: { body: string},
  applyDataCallback?: (value: string) => T,
): Promise<T | string> => { 
const body = typeof (applyDataCallback) === 'function'
    ? applyDataCallback(config.body)
    : config.body;

return body;

}

When using this function, even with a generic type provided, the value will always be a Promise<string | number>.

While this setup makes sense, I want the function to behave differently. If either the applyDataCallback parameter or the generic type is provided, I only want the value to be that generic type. In the current case shown in the screenshot, where both the generic type and applyDataCallback are provided, I still end up with a possible string as a result.

Any suggestions on how to address this scenario?

https://i.sstatic.net/dLG1k.png

Answer №1

To solve this issue, the best approach is to include a default function for applyDataCallback. This function will automatically convert the value type to the specified generic type.

applyDataCallback: (value: string) => T = (value) => value as T.

Make sure to always utilize this callback in your code.

const response = applyDataCallback(config.response)

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