What is the best way to create an "equals" method for an interface in mongodb?

export interface IHealthPlanCard {
    _id: string,
    statusId: string;
}

const cards: IHealthPlanCard[] = await healthPlanCardsCollection.find(...)
cards.filter(card => card.statusId.equals(cardStatusId))

I encountered an issue in this scenario: An error occurred stating: 'equals' does not exist on type 'string'.ts(2339)

I am unable to use the following syntax:

export interface IHealthPlanCard {
    _id: string,
    statusId: string | eqauls;
}

Answer №1

When working with MongoDB (or mongoose) and managing ObjectIds, it is recommended to always utilize the ObjectId type instead of string:

import { ObjectId } from "mongodb"
// import { Types } from "mongoose"

export interface IHealthPlanCard {
  _id: string,
  statusId: ObjectId;
}

const cards: IHealthPlanCard[] = await healthPlanCardsCollection.find(...)
cards.filter(card => card.statusId.equals(cardStatusId))

This approach will only be effective if you have set up your schema to use ObjectId rather than string.

By implementing this change, your ObjectIds will now have access to the .equals() method.

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