What is the best way to display just one record that has the lowest score out of all the records?

Question

What is the best way to display just one record that has the lowest score out of all the records?

I need help with displaying only 1 record from the DL list that has the lowest score, instead of showing all records.

In the example on stackblitz, you can see that for the first record, the DL scores are: 54, 20, and updated.

Instead of displaying all 3 records, I want to show only the record with the least score, which is 20.

Please provide suggestions.

Markup

<ul>
<li *ngFor="let assignee of user.assigned_to">
{{assignee.dl}} {{assignee.co_score}}
</li>
</ul>

Live https://stackblitz.com/edit/angular-ivy-1tsz1r?file=src%2Fapp%2Fapp.component.html

javascript arrays angular typescript filter

Answer 1

Answer №1

If you're looking for a practical demonstration, check out this StackBlitz link

A custom pipe has been developed to efficiently filter data...

The custom pipe code is as follows:

import { Pipe, PipeTransform } from "@angular/core";

@Pipe({
  name: "filterDL"
})

export class FilterDLPipe implements PipeTransform {
     transform(value: any, args?: any): any {
        console.log("filter pipe ", value);
        let filter = value.filter(item => Number(item.co_score));
        let leastScrore = Math.min(...filter.map(item => item.co_score));
        let findIndex = filter.filter(item => item.co_score === leastScrore);
        console.log("findex", findIndex);
        console.log(leastScrore);
      return findIndex;
    }
}

To use this pipe, apply it to your DL array to effectively filter the array.

<ul>
     <li *ngFor="let assignee of user.assigned_to | filterDL">
                {{assignee.dl}} {{assignee.co_score}}
     </li>
</ul>

You'll then receive the minimum score output in DL that you desire.

Answer 2

If you're looking for a practical demonstration, check out this StackBlitz link

A custom pipe has been developed to efficiently filter data...

The custom pipe code is as follows:

import { Pipe, PipeTransform } from "@angular/core";

@Pipe({
  name: "filterDL"
})

export class FilterDLPipe implements PipeTransform {
     transform(value: any, args?: any): any {
        console.log("filter pipe ", value);
        let filter = value.filter(item => Number(item.co_score));
        let leastScrore = Math.min(...filter.map(item => item.co_score));
        let findIndex = filter.filter(item => item.co_score === leastScrore);
        console.log("findex", findIndex);
        console.log(leastScrore);
      return findIndex;
    }
}

To use this pipe, apply it to your DL array to effectively filter the array.

<ul>
     <li *ngFor="let assignee of user.assigned_to | filterDL">
                {{assignee.dl}} {{assignee.co_score}}
     </li>
</ul>

You'll then receive the minimum score output in DL that you desire.

Answer 3

Answer №2

An idea to consider is locating the minimum value in a single step and providing the corresponding index, then accessing the element at that index from the designated array in the subsequent step. For further exploration, delve into the capabilities of the filter and find functions within the Array

Answer 4

An idea to consider is locating the minimum value in a single step and providing the corresponding index, then accessing the element at that index from the designated array in the subsequent step. For further exploration, delve into the capabilities of the filter and find functions within the Array

What is the best way to display just one record that has the lowest score out of all the records?

Answer №1

Answer №2

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