If I have a specified type like this:
type Template = {
a: string;
b: string;
c: string
}
I want to utilize it within a function, but with an additional parameter. How can I achieve this efficiently?
When attempting to extend the type, TypeScript indicates ? expected
This is how I attempted it:
const test = (template: Template extends { d: string }[]) => {
template.map(t => console.log(t.d));
}
Note: I prefer not to use [key:string]: string for defining this type.
Expanding types is not a feasible option. Reference the solution in this approved response.
To rectify your issue, consider implementing something along these lines:
type Template = {
a: string;
b: string;
c: string
}
type NewTemplate = Template & { d: string }
const test = (template: NewTemplate[]) => {
template.map(t => console.log(t.d));
}
If one prefers not to utilize '&' when extending the type, they have the option to create a generic function:
const example = <T extends Model>(model: T[]) => {
model.map(m => console.log(m.d))
}
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