What is the best way to implement generics for a zip function in TypeScript?

I want to enhance this JS function by including types:

function zip(array1, array2) {
  const length = Math.min(array1.length, array2.length);
  const result = [];
  for (let i = 0; i < length; i++) {
    result.push([array1[i], array2[i]]);
  }
  return result;
}

const res = zip(["1","2","3"], [4,5,6])

The output of res looks like this:

[["1",4],["2",5],["3",6]]

Up to this point, I have come up with the following code snippet, but it has a flaw, as the result type does not differentiate between a string and a number, considering them both as possible types:

function zip<T,U>(array1: T[], array2: U[]): (T|U)[][] {
  const length = Math.min(array1.length, array2.length);
  const result = [];
  for (let i = 0; i < length; i++) {
    result.push([array1[i], array2[i]]);
  }
  return result;
}

const res = zip(["1","2","3"], [4,5,6])

Answer №1

In addition to the answer provided by @apokryfos, you may want to explore the generator-based approach:

function* combineArrays<T,U>(arr1: T[], arr2: U[]): Generator<[T, U]> {
  const length = Math.min(arr1.length, arr2.length);
  for (let i = 0; i < length; i++) {
    yield [arr1[i], arr2[i]];
  }
}

const result = combineArrays(["a","b","c"], [1,2,3]);
for (const [x, y] of result) {
  console.log(`${x} ${y}`);
}

Answer №2

When working with TypeScript, the zip function is used to create an array of tuples with specific types:

function zipNumbersAndStrings<T,U>(numbers: T[], strings: U[]): [ T, U ][] {
  const length = Math.min(numbers.length, strings.length);
  const result: [ T, U ][] = [];
  for (let i = 0; i < length; i++) {
    result.push([numbers[i], strings[i]]);
  }
  return result;
}

const zippedData = zipNumbersAndStrings([1, 2, 3], ['a', 'b', 'c']);

This function ensures that each tuple in the result array contains a number followed by a string.

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