What is the best way to implement more elegant object access code?

I am facing some issues with TypeScript object access. Consider the following code snippet:

enum DataTypes {...}
class Cache {
    private _data: Partial<Record<DataTypes, Data>> = {};
    private getExpensiveData(name: DataTypes): Data {...}
    private get(name: DataTypes) {
        if(!(name in this._data)) {
            this._data[name] = this.getExpensiveData(name)
        }
        return this._data[name] //return type Data | undefined
    }
}

Currently, I am only able to write the last line of get function as return this._data[name] as Data. Is there a more elegant way to achieve this?

I apologize for not explaining clearly earlier, but what I'm trying to ask is if there's a method to make TypeScript infer it as not null without using as.

Answer №1

To streamline your code, consider using the null-coalescing operator in conjunction with augmented assignment:

return this._data[name] ??= this.getExpensiveData(name);

Utilizing the ?? operator allows for efficient evaluation as it will only process the right-hand side if the left-hand side is either undefined or null.

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