What is the best way to integrate functions using an interface along with types?

Currently, I am working on a school project that requires me to develop a type-safe LINQ in Typescript using advanced types.

I am facing a challenge in figuring out how to ensure all my tables (types) can utilize the same interface.

My goal is to be able to chain functions like the following example:

students.Select("Name", "Surname").Include("Grades", q =>
  q.Select("Grade", "CourseId" )
)

To start off, I defined a type Student and created a table students with some sample values:

type Student = {
    Name: string,
    Surname: string
}

let students: Student[] = [
    {Name: "Foo", Surname: "Bar"},
    {Name: "John", Surname: "Wick"}
]

I wanted to combine this setup with an interface to avoid repeating the Select function multiple times.

interface Entity<T> {
    Select: (args: T[]) => T
}

However, attempting to merge them using type Student = Entity<T> & { does not seem to work as it would require adding a generic type T to the students table and creating a separate Select for each type.

How can I ensure that the students table can leverage functions from Entity<T> and chain them together as shown in the initial example? Or should I consider approaching the problem differently?

If more details are needed, I am happy to provide them without making this explanation too lengthy.

Answer №1

Adding methods to the Array object in JavaScript can be done, but it is not recommended due to potential conflicts (imagine if a library also added a method with the same name!)

Instead, creating a new type that extends the basic Array type is a better approach:

class CustomArray<T> extends Array<T> {
    CustomMethod(...args: T[]): CustomArray<T> {
        // Implementation
    }
}

let data: CustomArray<Data> = new CustomArray();
data.push({Attribute: "Value"});
data.push({Attribute: "Another Value"});

// Example of using the custom method
data.CustomMethod("property");

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