What is the best way to invoke a function with multiple parameters in TypeScript?

I have a function that manipulates a specified query string, along with another version that always uses window.location.search. Here is the code snippet:

class MyClass {
  public changeQuery(query: string; exclude: boolean = true; ...values: string[]): string {
    // code logic here
  }

  public getQuery(exclude: boolean = true; ...values: string[]): string {
    let args: any[] = [...values];

    args.unshift(exclude);
    args.unshift(window.location.search);

    return this.changeQuery.apply(this, args); // <-- Error occurs @args
  }
}

An error message is appearing:

Argument of type 'any[]' is not assignable to parameter of type '[string, (boolean | undefined)?, ...string[]]'. Property '0' is missing in type 'any[]' but required in type '[string, (boolean | undefined)?, ...string[]]'.

To resolve this issue, I believe the variable let args needs to be defined differently. But what would be the correct definition? Alternatively, is it possible to make the parameter query: string optional in the updateQuery function and set it as window.location.search if no value is provided?

Answer №1

Aluan Haddad seems to have nailed it with the correct answer, all without even providing one. My mind was stuck on javascript, causing me to overcomplicate things.

public getQuery(exclude: boolean = true; ...values: string[]): string {
  return this.changeQuery(window.location.search, exclude, ...values);
}

It's working flawlessly, generating this javascript output:

getQuery(exclude = true, ...values) {
    let args = [...values];
    args.unshift(exclude);
    args.unshift(window.location.search);
    return this.changeQuery.apply(this, args);
}

This appears to be the code snippet I attempted to implement in typescript.

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