What is the best way to mock a Typescript interface or type definition?

In my current project, I am working with Typescript on an AngularJS 1.X application. I make use of various Javascript libraries for different functionalities. While unit testing my code, I am interested in stubbing some dependencies using the Typings (interfaces). However, I want to avoid using the ANY type and do not want to create empty methods for each interface method.

I am searching for a solution that allows me to achieve something like this:

let dependency = stub(IDependency);
stub(dependency.b(), () => {console.log("Hello World")});
dependency.a(); // --> Compile, no action taken, no exception
dependency.b(); // --> Compile, print "Hello World", no exception

Currently, I am facing the dilemma of either using any and implementing all methods called in my test cases or fully implementing the interface, resulting in excessive and unnecessary code.

Is there a way to generate an object with empty implementations for each method while maintaining typing? I currently utilize Sinon for mocking purposes but I am open to exploring other libraries as well.

PS: Despite being aware that Typescript erases interfaces, I am still determined to find a solution for this issue :).

Answer №1

When it comes to writing Typescript tests using qUnit and Sinon, I can definitely relate to the challenges you're facing.

Imagine having a dependency on an interface like this:

interface IDependency {
    a(): void;
    b(): boolean;
}

To tackle this without relying on additional tools or libraries, I've adopted a couple of strategies involving sinon stubs/spies and casting.

  • The first approach involves utilizing an empty object literal where you assign sinon stubs directly to the required functions:

    //Create an empty literal as your IDependency 
    let anotherDependencyStub = <IDependency>{};
    
    //Assign stubs for each method used in your code
    anotherDependencyStub.a = sandbox.stub();
    anotherDependencyStub.b = sandbox.stub().returns(true);
    
    //Proceed with your code execution and expectation verifications
    dependencyStub.a();
    ok(anotherDependencyStub.b());
    sinon.assert.calledOnce(<SinonStub>anotherDependencyStub.b);
    
  • The second option involves employing an object literal with empty method implementations, subsequently wrapping these methods in sinon spies/stubs as needed:

    //Create a dummy interface implementation with only the necessary methods
    let dependencyStub = <IDependency>{
        a: () => { },
        b: () => { return false; }
    };
    
    //Set up spies/stubs
    let bStub = sandbox.stub(dependencyStub, "b").returns(true);
    
    //Execute your code and verify expectations
    dependencyStub.a();
    ok(dependencyStub.b());
    sinon.assert.calledOnce(bStub);
    

These approaches interact seamlessly when combined with sinon sandboxes and standard setup/teardown procedures provided by qUnit modules.

  • Create a new sandbox and mock object literals for dependencies during setup.
  • Specify the spies/stubs within the test itself.

This structure (illustrated using the first option) could look something like:

QUnit["module"]("fooModule", {
    setup: () => {
        sandbox = sinon.sandbox.create();
        dependencyMock = <IDependency>{};
    },
    teardown: () => {
        sandbox.restore();
    }
});

test("My foo test", () => {
    dependencyMock.b = sandbox.stub().returns(true);

    var myCodeUnderTest = new Bar(dependencyMock);
    var result = myCodeUnderTest.doSomething();

    equal(result, 42, "Bar.doSomething returns 42 when IDependency.b returns true");
});

While not a perfect solution, this method proves effective without the need for extra libraries while maintaining a manageable level of additional code.

Answer №2

The latest version of TypeMoq (ver 1.0.2) now has the ability to mock TypeScript interfaces, provided that the runtime environment (nodejs/browser) supports the ES6 introduced Proxy global object.

For instance, if we have an interface called IDependency defined as follows:

interface IDependency {
    a(): number;
    b(): string;
}

We can easily mock it using TypeMoq like this:

import * as TypeMoq from "typemoq";
...
let mock = TypeMoq.Mock.ofType<IDependency>();

mock.setup(x => x.b()).returns(() => "Hello World");

expect(mock.object.a()).to.eq(undefined);
expect(mock.object.b()).to.eq("Hello World");

Answer №3

In Typescript, it seems that achieving reflection is not possible as the language lacks support for compile-time or run-time "reflection". This limitation makes it impossible for a mock library to iterate through the members of an interface.

For more information, refer to this thread: https://github.com/Microsoft/TypeScript/issues/1549

This poses a challenge for TDD developers who heavily rely on mocking dependencies in their development process.

Although traditional methods may not work, there are alternate techniques available for quickly stubbing methods, as discussed in other responses. These approaches may require some adaptation but could still be effective.

Additionally, it's worth noting that while Typescript lacks run-time reflection, its Abstract Syntax Tree (AST) can be used for compile-time "introspection". There might be possibilities to leverage this feature to generate mocks, although no practical libraries have been developed so far.

Answer №4

Here is some information from npmjs:

Mocking interfaces
You have the ability to mock interfaces as well by setting the generic type for the mock function, which requires Proxy implementation.

let mockedFoo:Foo = mock<FooInterface>(); // instead of mock(FooInterface)
const foo: SampleGeneric<FooInterface> = instance(mockedFoo);

It's worth noting that ts-mockito started supporting mocking interfaces since version 2.4.0:

Answer №5

If you're looking to mock libraries, there are a handful of options available such as TypeMoq, TeddyMocks, and Typescript-mockify which are quite popular choices.

For more information and to decide which one suits your needs best, you can explore their respective GitHub repositories: links:

If you prefer using more mainstream libraries like Sinon, make sure to initially define the type as <any>, then refine it to <IDependency> type (check this link for more details: How do I use Sinon with Typescript?)

Answer №6

If you're looking for a testing library, consider checking out moq.ts. It relies on the Proxy object for functionality.

interface IDependency {
  a(): number;
  b(): string;
}


import {Mock, It, Times} from 'moq.ts';

const mock = new Mock<IDependency>()
  .setup(instance => instance.a())
  .returns(1);

mock.object().a(); //returns 1

mock.verify(instance => instance.a());//pass
mock.verify(instance => instance.b());//fail

Answer №7

SafeMock Tool offers a great solution for safe mocking, but unfortunately, it appears to be inactive now. Just to be transparent, I have previously collaborated with the developer.

import SafeMock, {check} from "safe-mock-tool";

const mock = SafeMock.create<SomeService>();

// set specific return values based on provided arguments
when(mock.someMethod(123, "some arg")).return("expectedReturn");

// define exceptions when method is called with certain arguments
when(mock.someMethod(123, "some arg")).throw(new Error("It's freezing!")); 

// configure the mock to return rejected promises 
when(mock.someMethod(123)).reject(new Error("It's freezing!"));

//use verify.calledWith to confirm the exact arguments passed to a mocked method
verify(mock.someMethod).calledWith(123, "someArg");

SafeMock Tool ensures that the correct data type is returned by mocks.

interface SomeService {
    createSomething(): string;
}

const mock: Mock<SomeService> = SafeMock.build<SomeService>();

//The following won't compile as createSomething expects a string return value
when(mock.createSomething()).return(123); 

Answer №8

Seize the opportunity. An updated version of the typescript compiler has been unleashed, granting access to interfaces metadata during runtime. For instance, you can now input:

interface Something {

}

interface SomethingElse {
    id: number;
}

interface MyService {
    simpleMethod(): void;
    doSomething(p1: number): string;
    doSomethingElse<T extends SomethingElse>(p1: Something): T;
}

function printMethods(interf: Interface) {
    let fields = interf.members.filter(m => m.type.kind === 'function'); //exclude methods.
    for(let field of fields) {
        let method = <FunctionType>field.type;
        console.log(`Method name: ${method.name}`);
        for(let signature of method.signatures) {
            //you can delve deeper here, refer to reflection.d.ts for API details
            console.log(`\tSignature parameters: ${signature.parameters.length} - return type kind: ${signature.returns.kind}`);
            if(signature.typeParameters) {
                for(let typeParam of signature.typeParameters) {
                    console.log(`\tSignature type param: ${typeParam.name}`); //constraints can be obtained using typeParam.constraints
                }
            }
            console.log('\t-----')
        }
    }
}

printMethods(MyService); //now usable as a literal!!

This will generate the following output:

$ node main.js
Method name: simpleMethod
        Signature parameters: 0 - return type kind: void
        -----
Method name: doSomething
        Signature parameters: 1 - return type kind: string
        -----
Method name: doSomethingElse
        Signature parameters: 1 - return type kind: parameter
        Signature type param: T
        -----

Armed with this wealth of information, you have the ability to construct stubs programmatically according to your preferences.

Feel free to explore my project here.

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